(2x-4)/(x^2-4x+4)

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Solution for (2x-4)/(x^2-4x+4) equation: 


D( x )

x^2-(4*x)+4 = 0

x^2-(4*x)+4 = 0

x^2-(4*x)+4 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

x in (-oo:2) U (2:+oo)

(2*x-4)/(x^2-(4*x)+4) = 0

(2*x-4)/(x^2-4*x+4) = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

(x-2)^2 = 0

(2*x-4)/((x-2)^2) = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in { 2} 

x belongs to the empty set

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